145k views
4 votes
5

Find the value of n, if f(x) = 2x^2n - 4x^n - 5 has a remainder of 11 when divided
by 2x - 1​

1 Answer

3 votes

f(x)=2x*2n-4x*n-5

when f(x)÷2x-1,

the remainder=f(1/2)

f(1/2)=11

2(1/2)*2n-4(1/2)*n-5=11

1*2n-2*n-5=11

-2*n=11+5[any power of 1=1]

(-1)2*n=16

(-1)2*n=2*4

(-1)n=4[because equal base]

-n=4

n=-4

User Buddhi
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories