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What is the y- value of the vertex of 4c^2+8x-8

User Snifff
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1 Answer

4 votes

Answer:

a =4 b=8 c=-8

y-value of vertex =

ah^2 + bh + c

where h = -b/2a

h= -8/8 =-1

y-value of vertex =

4(-1)^2 + 8*-1 -8

4 -8 -8

y value of vertex = -12

Explanation:

User Nono
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