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A sample of a compound analyzed in a chemistry laboratory consists of 5.34 g of carbon, 0.42 g of hydrogen, and 47.08 g of chlorine. What is the percent composition of this compound?

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Answer:

10.1 % Carbon, 0.8 % Hydrogen and 89.1 % Chlorine.

Step-by-step explanation:

The total mass of the compound is 5.34 + 0.42 + 47.08 = 52.84 g.

The percentage of carbon is:
(5.34)/(52.84) × 100 = 10.1 %

The percentage of hydrogen is:
(0.42)/(52.84) × 100 = 0.8 %

The percentage if chlorine is:
(47.08)/(52.84) × 100 = 89.1 %

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