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Find the value of x so that the line passing through (x, 10) and (-4, 8) has a slope of 2/3

User WebbySmart
by
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2 Answers

4 votes

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cut point with ele axis and


m = \frac {y2-y1} {x2-x1}

How we have:


\frac {2} {3} = \frac {8-10} {- 4-x}\\\frac {8-10} {- 4-x} = \frac {2} {3}\\\frac {-2} {- 4-x} = \frac {2} {3}

We clear the value of "x"


2 (-4-x) = - 6\\-8-2x = -6\\-2x = -6 + 8\\-2x = 2\\x = \frac {2} {- 2}\\x = -1

Answer:


x = -1

User Sangimed
by
8.9k points
6 votes

Answer:

x = -1

Explanation:

We are given the following two points from which the line passes and has a slope of
(2)/(3).

We are to find the value of x.

Slope =
\frac { y _ 2 - y _ 1 } { x _ 2 - x _ 1 }


(2)/(3) =
(10-8)/(x-(-4))


(2)/(3) =
(2)/(x+4)

By cross multiplication:


2(x+4)=3 * 2


2x+8=6


2x=-2

x = -1

User Blang
by
8.3k points

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