Find the value of x so that the line passing through (x, 10) and (-4, 8) has a slope of 2/3

Question

asked Jan 23, 2020 45.9k views

2 Answers

Sangimed · Answer 1 · 2020-01-26T04:23:53+0000

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut point with ele axis and

$m = \frac {y2-y1} {x2-x1}$

How we have:

$\frac {2} {3} = \frac {8-10} {- 4-x}\\\frac {8-10} {- 4-x} = \frac {2} {3}\\\frac {-2} {- 4-x} = \frac {2} {3}$

We clear the value of "x"

$2 (-4-x) = - 6\\-8-2x = -6\\-2x = -6 + 8\\-2x = 2\\x = \frac {2} {- 2}\\x = -1$

Answer:

Blang · Answer 2 · 2020-01-30T04:25:08+0000

Answer:

x = -1

Explanation:

We are given the following two points from which the line passes and has a slope of
(2)/(3) .

We are to find the value of x.

Slope =
$\frac { y _ 2 - y _ 1 } { x _ 2 - x _ 1 }$

(2)/(3) =
(10-8)/(x-(-4))

(2)/(3) =
(2)/(x+4)

By cross multiplication:

2(x+4)=3 * 2

2x+8=6

2x=-2

x = -1