Question

Find the value of x so that the line passing through (x, 10) and (-4, 8) has a slope of 2/3

Answer 1

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

`y = mx + b`

Where:

m: It's the slope

b: It is the cut point with ele axis and

`m = \frac {y2-y1} {x2-x1}`

How we have:

`\frac {2} {3} = \frac {8-10} {- 4-x}\\\frac {8-10} {- 4-x} = \frac {2} {3}\\\frac {-2} {- 4-x} = \frac {2} {3}`

We clear the value of "x"

`2 (-4-x) = - 6\\-8-2x = -6\\-2x = -6 + 8\\-2x = 2\\x = \frac {2} {- 2}\\x = -1`

Answer:

`x = -1`

Answer 2

x = -1

Explanation:

We are given the following two points from which the line passes and has a slope of
`(2)/(3)`.

We are to find the value of x.

Slope =
`\frac { y _ 2 - y _ 1 } { x _ 2 - x _ 1 }`

`(2)/(3)` =
`(10-8)/(x-(-4))`

`(2)/(3)` =
`(2)/(x+4)`

By cross multiplication:

`2(x+4)=3 * 2`

`2x+8=6`

`2x=-2`

x = -1