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Someone help please!!!

Someone help please!!!-example-1

1 Answer

3 votes

Answer:

41.5 ft

Explanation:

From the information given, and definition of midpoint, we know that:

AB = BC = ½ AC

AC = CE = ½ AE

CD = DE = ½ CE

GF = FE = ½ GE

HG = GE = ½ HE

AI = IH = ½ AH

AJ = JI = ½ AI

We also know:

AH = 20

HE = 14

GD = 4

Therefore:

AI = IH = 10

HG = GE = 7

AJ = JI = 5

GF = FE = 7/2

Next, since JB and IC are parallel with HE, we know that AJB and AIC are similar to AEH. So:

JB / 5 = 14 / 20

JB = 7/2

IC / 10 = 14 / 20

IC = 7

And since DF and CG are parallel to AH, then DFE and DGE are similar to AHE. So:

DF / (7/2) = 20 / 14

DF = 5

CG / 7 = 20 / 14

CG = 10

Next we know that AIB and AHC are similar, and DEG and CEH are similar.

IB / 10 = CH / 20

CH / 14 = 4 / 7

CH = 8, IB = 4.

We've found all the lengths inside triangle AEH. Adding them up:

JB + IB + IC + CH + CG + DG + DF

7/2 + 4 + 7 + 8 + 10 + 4 + 5

41.5

The total length of the inside bars is 41.5 ft.

User Lisett
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