95.7k views
5 votes
What is the alternate form of CaF2+H2SO+157.7KJ→CaSO4+2HF

User Pontomedon
by
6.8k points

1 Answer

3 votes

Answer:

CaF₂+H₂SO₄ → CaSO₄+2HF ΔH = +157.7KJ

Step-by-step explanation:

Energy changes in chemical reactions is one of the most important issues in thermodynamics especially the enthalpy of reaction (ΔHrxn)

  • (ΔHrxn) can be defined as the difference between the total enthalpy of the products and the total enthalpy of the reactants of a certain reaction.

  • If ΔH<0 for an exothermic reaction (i.e. heat flows from a system to its surroundings) or in other words, the enthalpy of the products is less than the enthalpy of the reactants
  • While, ΔH>0 for an endothermic reaction (i.e. heat flows from the surroundings to a system) that means the enthalpy of the products is greater than the enthalpy of the reactants.
  • In this example

CaF₂+H₂SO₄+157.7KJ → CaSO₄+2HF

  • heat flows from the surroundings to a system and so ΔH>0

which can be expressed in alternate form as following

CaF₂+H₂SO₄ → CaSO₄+2HF ΔH = +157.7KJ

User Ivan Pirus
by
6.6k points