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Find the specific solution of the differential equation dy/dx= 4y/x^2 with condition y(-4)=1

A. y=-1-4/x
B. y=-e^1/x
C.y=e^(-4/x)
D. None of these

1 Answer

3 votes

This ODE is separable:


(\mathrm dy)/(\mathrm dx)=(4y)/(x^2)\implies\frac{\mathrm dy}y=\frac4{x^2}\,\mathrm dx

Integrating both sides gives


\ln|y|=-\frac4x+C

Given the initial condition
y(-4)=1 we find


\ln|1|=-\frac4{-4}+C\implies C=-1

so that the particular solution is


\ln|y|=-\frac4x-1


\implies y=e^(-(1+4/x)))

so the answer is D.

User Riegersn
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