428,626 views
7 votes
7 votes
If tan A 3/4 find the value of: sin2A​

User Alexander Poluektov
by
2.4k points

2 Answers

17 votes
17 votes

Answer:

24/25

Explanation:

use tan^-1 to find the angle

tan^-1(3/4)=36.86989765°

A =36.86989765°

2A= 2×36.86989765

=73.73979529°

sin2A>>>>sin(73.73979529°)

=24/25 or 0.96

User Kas Hunt
by
2.9k points
24 votes
24 votes

Answer:

sin2A =
(24)/(25)

Explanation:

using the identity

sin2A = 2sinAcosA

given

tan2A =
(3)/(4) =
(opposite)/(adjacent)

then this is a 3- 4- 5 right triangle with

hypotenuse = 5, opposite = 3 , adjacent = 4 , then

sinA =
(opposite)/(hypotenuse) =
(3)/(5) and cosA =
(adjacent)/(hypotenuse) =
(4)/(5)

Then

sin2A = 2 ×
(3)/(5) ×
(4)/(5) =
(2(3)(4))/(5(5)) =
(24)/(25)

User Teisha
by
2.5k points