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The equation of a parabola is given.

y=-1/12x^2 - 2x-1
What are the coordinates of the focus of the parabola?
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The equation of a parabola is given. y=-1/12x^2 - 2x-1 What are the coordinates of-example-1
User Sparker
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2 Answers

4 votes

Answer: -12, 8

Explanation:

User AJMansfield
by
8.2k points
6 votes

ANSWER

(-12,8)

EXPLANATION

The equation of the parabola is given as:


y = - (1)/(12) {x}^(2) - 2x - 1

We can rewrite this in the vertex form as:


{(x + 12)}^(2) = - 12(y - 11)

This implies that


4p = 12

p=3

The vertex of this parabola is (-12,11)

The focus is

(-12,11-3)

=(-12,8)

User Maana
by
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