93.1k views
5 votes
Solve for X

A: 12.5
B: 5
C: 6
√(3)
D:12

Solve for X A: 12.5 B: 5 C: 6√(3) D:12-example-1
User Matiiss
by
5.6k points

2 Answers

2 votes

bear in mind that, a perpendicular line stemming from the right-angle like so, creates three similar triangles, a large one, containing the other two smaller ones, a medium and a small.

so.. .we can just use the medium and small proportions.

Check the picture below.

Solve for X A: 12.5 B: 5 C: 6√(3) D:12-example-1
User Weng
by
6.0k points
5 votes

Answer:

D. 12

Explanation:

(LOOK AT THE PICTURE)

ΔADC and ΔCDB are similar (AAA). Therefore the corresponding sides are in proportion:


(AD)/(CD)=(CD)/(DB)

We have


AD=16,\ CD=x,\ DB=9

Substitute:


(16)/(x)=(x)/(9) cross multiply


x^2=(9)(16)\to x=√((9)(16))\\\\x=(\sqrt9)(√(16))\\\\x=(3)(4)\\\\x=12

Solve for X A: 12.5 B: 5 C: 6√(3) D:12-example-1
User Daniloisr
by
5.5k points