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Two cars started moving from San Jose to San Diego. The speed of the faster car was 12 mph less than twice the speed of the other one. In 6 hours the faster car got to San Diego, and by that time the slower one still was 168 miles away from the destination. Find their speeds.

User Cvrebert
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7.9k points

2 Answers

4 votes

Their speeds are 45 mi/hr and 49 mi/hr

User Doug Stephen
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6 votes

Answer:

The speed of the faster car is 68 miles/hr and speed of slower car is 40 miles/hr.

Explanation:

Let the speed of the slower car be x

Now we are given that The speed of the faster car was 12 mph less than twice the speed of the other one.

So, Speed of faster car = 2x-12

Now we are given that In 6 hours the faster car got to San Diego, and by that time the slower one still was 168 miles away from the destination.

So, faster car completes the journey in 6 hours

Distance =
Speed * Time

So, Distance traveled by faster car =
(2x-12)* 6

Distance traveled by slower car in 6 hours =
Speed * Time=6x

Since we are given that when faster car completes the journey at that time slower car was 168 miles away from the destination .

A.T.Q


(2x-12)* 6-6x=168


12x-72-6x=168


6x-72=168


6x=240


x=(240)/(6)


x=40

So, speed of slower car is 40 miles/hr.

Speed of faster car = 2x-12 =2(40)-12=80-12=68 miles/hr.

Hence the speed of the faster car is 68 miles/hr and speed of slower car is 40 miles/hr.

User Paul Gowder
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