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Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. How long will it take Sally to catch up with Jane?

2 Answers

3 votes

Answer:

10/3 hours

Explanation:

12x=15x-10

12x-15x=15x-10-15x

-3x=-10

-3x/-3=-10/-3

x=10/3

User Khtad
by
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2 votes

Answer: Sally will catch up with Jane after 50 minutes.

Explanation:

Since we have given that

Speed of Jane of biking = 12 mph

After 10 minutes,

Speed of Sally of biking = 15 mph

Let the distance be 'x'.

According to question, our required equation becomes,


(x)/(12)-(x)/(15)=(10)/(60)\\\\(5x-4x)/(60)=(1)/(6)\\\\(1x)/(60)=(1)/(6)\\\\x=10\ miles

Thus, total distance would be 10 miles.

So, the time taken by Sally to catch up with Jane is given by


(10)/(12)=(5)/(6)* 60=50\ minutes

Hence, Sally will catch up with Jane after 50 minutes.

User Jwqq
by
5.2k points