Answer:
Option: a is the correct answer.
(a) 1
Explanation:
- Let the input of Feynman be denoted by i and it's output be denoted by f.
Now, it is given that:
Feynman, produces output, that is 5 times its input followed by an increase of 2.
i.e. the equation that will be formed using this information is:

The output of Feynman feeds into Maxwell.
Let the output of Maxwell be denoted by m and it's input is f.
Maxwell, produces output, that is 5 times its input followed by a decrease of 2.
This means that the equation that will be formed using this information is:

Now, we put the value of f from equation (1) into equation (2)
i.e.

If the output of Maxwell is: 33
i.e.

Then

Hence, the input of Feynman is: 1