Question

The yearly income for an individual with an associate’s degree in 2001 was $53,166 and in 2003 it was $56,970. What is the ratio of the income in 2001 to the income in 2003 in simplest form?

Answer 1

8861 : 9495

Explanation:

Ratio of income in 2001 to 2003:

53,166 : 56,970

Then, you can simplify by dividing both sides by 6:

8,861 : 9,495

Can't simplify anymore, Therefore this is the answer!

8861 : 9495

Hope I helped! Have a good day :)

Answer 2

`(8861)/(9495)`

Explanation:

Income of an individual in 2001 =
`\$ 53,166`

Income of an individual in 2003 =
`\$ 56,970`

Here, we need to find ratio of income in 2001 to the income in 2003 in simplest form .

i.e we need to convert
`(\$53,166)/(\$ 56,970)` in simplest form .

A fraction
`(a)/(b)` is said to be in simplest form if
`HCF(a,b)=1`

So, we will first find
`HCF(53166,56970)` then divide both numerator and denominator by the HCF .

Here,

`53166=2* 3* 8861`

`56970=2* 3* 3* 3* 5* 211`

So,
`HCF(53166,56970)=2* 3=6`

On dividing both numerator and denominator by 6 , we get

`(53166)/(56970)=(8861)/(9495)`