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Divide the polynomial x^3+x^2-2x+3 by (x-1)​

User OMGPOP
by
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1 Answer

3 votes

Answer:

+ 2x + (3 / (x − 1))

Explanation:

Start by setting up the division:

.........____________

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³. Divided by x, that's x². So:

.........__________

x − 1 | x³ + x² − 2x + 3

Multiply x − 1 by x², subtract the result, and drop down the next term:

.........__________

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Repeat the process over again. First term is 2x². Divided by x is 2x. So:

.........____+ 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Multiply, subtract the result, and drop down the next term:

.........____+ 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

.................-(2x² − 2x)

.................---------------

.....................................3

x doesn't divide into 3, so that's the remainder.

Therefore, the answer is:

+ 2x + (3 / (x − 1))

User Tejas Patel
by
6.0k points