Question

If g(x)= square root x-2-3 what is the range of g(x)? A.(0,♾) B. (-1,♾) C. [-2,♾) D. [-3,♾)​

Answer 1

D

Explanation:

g(x) = √(x - 2) - 3

The range is all the possible values of g(x). Since we can't take the square root of a negative number, the lowest that g(x) can be is:

g(x) = √0 - 3

g(x) = -3

The highest that g(x) can be is:

g(x) = √∞ - 3

g(x) = ∞

So the range is:

[-3, ∞)