194k views
3 votes
Please help........​

Please help........​-example-1
User Konza
by
7.5k points

1 Answer

5 votes


\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ \cline{1-1} V=36\pi \end{cases}\implies 36\pi =\cfrac{4\pi r^3}{3}\implies 108\pi =4\pi r^3 \\\\\\ \cfrac{108\pi }{4\pi }=r^3\implies 27=r^3\implies \sqrt[3]{27}=r\implies \boxed{3=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies SA=4\pi \left( \boxed{3} \right)^2\implies SA=4\pi (9)\implies SA=36\pi

User Mae
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories