Question

A can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company’s clients needs a cylindrical can that has the same volume but is 15 cm tall. What must the new radius be to meet the client’s need? Round to the nearest tenth of a centimeter.

2.7 cm
4.9 cm
7.3 cm
24.0 cm

Answer 1

the anwser is 4.9

Explanation:

Answer 2

4.9 cm

Explanation:

The original can has a volume of ...

V = πr²h = π(6 cm)²(10 cm) = 360π cm³

The new can will have the same volume, but a different height:

360π cm³ = πr²(15 cm)

24 cm² = r² . . . . . divide by 15π cm

r = √24 cm ≈ 4.9 cm . . . . . take the square root

The new radius must be about 4.9 cm.