Answer: Option 'A' is correct
Explanation:
Since we have given that
A be the event that Ashley drives faster than the speed limit.
P(A)=0.34
B be the event that he gets a speeding ticket.
P(B)=0.22
Probability that he drives faster than the speed limit, given that he has gotten a speeding ticket i.e.
P(A|B)=1
but for A and B to be independent ,
P(A).P(B)= P(A and B)
0.34×0.22=0.0748
but,
![P(A\mid B)=(P(A\cap B))/(P(B))\\\\1=(P(A\cap B))/(0.22)\\\\0.22=P(A\cap B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5vxmzk251f8wiy5sn3a7lgnwjjynxojbbl.png)
So, P(A∩B) does not satisfy the condition.
Hence, A and B are not independent events.
Option 'A' is correct as they are dependent events.