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A line passes through the points (2,4) and (-4,-1). Find its equation in slope-intercept form. (2 points, 1 for work, 1 for equation)

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Hello!

The answer is:

The equation of the line in slope-intercept form:


y=(5)/(6)x+(7)/(3)

Why?

To find the equation in slope-intercept form, we need to follow the next steps:

Find the slope of the line:

Using the slope formula, we have:


m=(y_2-y_1)/(x_2-x_1)

We are given the points:


(2,4)\\(-4,-1)

So, substituting we have:


m=((-1)-(4))/(-4-2)


m=(-5)/(-6)


m=(5)/(6)

Find the "b" value:

Now that we know the value of the slope, we can write the equation of the line:


y=(5)/(6)x+b

In order to find "b" we need to substituite any of the given points, we know that line is thru both of the given points, so, substituting (2,4) we have:


4=(5)/(6)*2+b\\\\4=(10)/(6)+b\\\\4=(5)/(3)+b\\\\b=4-(5)/(3)=\frac{(3*4)-5}3}=(12-5)/(3)=(7)/(3)

Now that we know the slope and "b", we can write the equation of the line in slope-intercept form:


y=(5)/(6)x+(7)/(3)

Have a nice day!

User Ptitzler
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