Question

What is the general form of the equation of the line shown?

Answer 1

The desired equation is y = (-8/3)x + 3.

Explanation:

There's no one general form; several different forms apply here.

Seeing that the y-intercept is (0, 3) and that another point on the line is (3, -5), I'd use the slope-intercept form here: y = mx + b

As we move from the first point to the second, x increases by 3 and y decreases by 8. Thus, the slope of the line through the two points is

m = rise / run = -8/3. As before, the y-intercept is (0, 3), so b = 3.

The desired equation is y = (-8/3)x + 3.

Answer 2

Hello!

The answer is:

The first option:

`3x+y-3=0`

Why?

To find which is the equation of the line shown, we need to find a line that intercepts the y-axis at 3 and the x-axis and 1.

So, discarding we have:

First equation:

`3x+y-3=0`

Making "x" equal to 0 in order to find the y-axis intercept, we have:

`3(0)+y-3=0`

`y=3`

Making "y" equal to 0 in order to find the x-axis intercept, we have:

`3x+0-3=0`

`3x=3`

`x=(3)/(3)=1`

So, we have found that the x-axis and y-axis intercept of the equation, are the shown in the picture.

The interception points of the equation and the line are:

For x-axis:

`(1,0)`

For y-axis:

`(0,3)`

Hence, the answer is the first option.

`3x+y-3=0`

Have a nice day!