Question

An expandable container of oxygen gas has a volume of 125 mL and a temperature of 25.0?C. What volume will the gas occupy at 55°C?

Answer 1

137.6 mL.

Step-by-step explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

• If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

• Knowing that:

V₁ = 125.0 mL, T₁ = 25°C + 273 = 298 K,

V₂ = ??? mL, T₂ = 55°C + 273 = 328 K,

• Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (125.0 mL)(328 K)/(298 K) = 137.6 mL.