Question

(Quadratics) find the maximum of -16x^2 + 64x +8

Answer 1

The max of this function is 72.

Step-by-step explanation: -b

The x-coordinate of the vertex is given by x = ---------

2(a)

which in this case is x = 2.

The value of -16x^2 + 64x +8 at x = 2 is f(2) = 72.

The max of this function is 72.