You have to do Pythagorean theorem:
![a^(2) +b^(2) = c^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8fbpx1xo89t1y4f0srhyii3efapygtgpy4.png)
"a" and "b" are the legs. In this case 7 is a leg and x is a leg
"c" is the hypotenuses, which is 19 here
so...
a = 7
b = x
c = 19
Plug the numbers above into the equation:
![7^(2) + x^(2) = 19^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nu7q9ba0qiz2f3ujaplriew03icp5rnkwx.png)
![49 +x^(2) = 361](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cpwh318i1vejr57abnwqmxi6iqjzobj6or.png)
Isolate x by subtracting 49 to both sides:
![(49-49) + x^(2) = 361 - 49](https://img.qammunity.org/2020/formulas/mathematics/middle-school/77x28nbus6bqfe3x62smz1ltmu621vbe3o.png)
![x^(2) = 312](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ex87c3dourcehlt1buk79dkdhu15up7mbm.png)
To solve for x you have to take the square root to both sides of the equation:
![\sqrt{x^(2) } = √(312)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bgkpcvdgeiqbcufhwx7t1kxlapia06re06.png)
x = 17.6635
x = 17.7
Hope this helped!