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For what values of x is x^2 +2x=24 true

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{x}^(2) + 2x = 24 \\ {x}^(2) + 2x - 24 = 0 \\ {x}^(2) + (6x - 4x) - 24 = 0 \\ ({x}^(2) + 6x) - (4x + 24) = 0 \\ x(x + 6) - 4(x + 6) = 0 \\ (x - 4)(x + 6) =0 \\ \\ therefore \: \: the \: values \: of \: x \: are \: 4 \: and \: - 6.

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User Smelch
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2 votes

Answer: x=4, x=-6

Explanation:

set the equation equal to 0. solve for the x using the x method.

User Sasker
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