What is the range of the function y=2e^x-1 all real numbers less than –1 all real numbers greater than –1 all real numbers less than 1 all real numbers greater than 1

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asked Dec 15, 2020 151k views

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Gaurav Jassal · Answer 1 · 2020-12-16T14:23:19+0000

Answer:Answer: All real numbers greater than -1. Step-by-step explanation: We have to find the range of: y= 2e^x-1. We know that e^x lies in (0,∞). Hence, 2e^x lies in (0,∞). Hence, 2e^x-1 lies in (-1 ...

Step-by-step explanation:Answer: All real numbers greater than -1. Step-by-step explanation: We have to find the range of: y= 2e^x-1. We know that e^x lies in (0,∞). Hence, 2e^x lies in (0,∞). Hence, 2e^x-1 lies in (-1 ...

Nadunc · Answer 2 · 2020-12-19T02:08:51+0000

Answer:

B. All real numbers greater than –1.

Explanation:

We have been given a function
y=2e^x-1 . We are asked to find the range of our given function.

We know that the range of an exponential function
$f(x)=c\cdot n^(ax+b)+k$ is
f(x)>k .

Upon looking at our given function, we can see that
k=-1 , therefore, the range of our given function would be
that is all real numbers greater than
.

What is the range of the function y=2e^x-1 all real numbers less than –1 all real numbers greater than –1 all real numbers less than 1 all real numbers greater than 1

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