Question

The function f(x)=x^2+4.2x+3.6 has an axis of symmetof x=-2-. What is the minimum value of the function

Answer 1

The minimum value is -0.8

Step-by-step explanation

The given

`f(x)=x^2+4.2x+3.6`

The minimum value is the y-value of the vertex (minimum point).

To find the minimum value of the function, we substitute x=-2 into the function to get;

`f( - 2)=( - 2)^2+4.2( - 2)+3.6`

`f( - 2)=4 - 8.4+3.6 = - 0.8`

The minimum value is -0.8