Answer:
Option C. is the correct option.
Explanation:
A bag contains 10 red, 6 blue and 4 green jelly beans.
A jelly bean is chosen at random from the bag then probability that the ball is blue will be =
![\frac{\text{Total number of blue balls}}{\text{Total number of balls in the bag}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/emje2qjg3h8vdue2nvhurc8z58z99slxm5.png)
P(B) =
![(6)/(20)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yzc0nrqcab1lgsqenmy0eqzjxwj20s6gih.png)
Now we know that probability that the ball picked from the bag is not blue
= 1 - P(B)
= 1 -
![(6)/(20)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yzc0nrqcab1lgsqenmy0eqzjxwj20s6gih.png)
=
![(20 - 6)/(20)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fp3a30aa8dl9a2741tvtemss39ouvz4bl2.png)
=
![(14)/(20)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8ks6p7bv42lmy4rz3lo5nhyq91bp8swqxf.png)
=
![(7)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rx7uu4995jmld2457yw4kncm86qrlnpy50.png)
Therefore, option C. is the correct option.