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Extraneous solution q-6= square root 27-2q

1 Answer

3 votes

Answer:

q = 1, q = 9

Explanation:

Equation: q - 6 = √(27 - 2q)

Exponents: (q - 6)² = 27 - 2q

Simplify: q² - 12q + 36 = 27 - 2q

Subtract: q² - 10q + 9 = 0

Two numbers: a + b = -10, ab = 9 --> a = -1, b = -9

Substitute: q² - 1q - 9q + 9 = 0

Simplify: (q - 1)(q - 9) = 0

Solve: q - 1 = 0, q - 9 = 0 --> q = 1, q = 9

User Anthony Awuley
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