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4x+2y=0 3x-y=-10 solve the system

1 Answer

5 votes

Divide the first equation by 2:


\begin{cases}2x+y=0\\3x-y=-10\end{cases}

Sum the two equations:


5x = -10

Divide both sides by 5:


x=-2

Substitute this value for x in one of the equation (for example the first) and solve for y:


-8+2y = 0 \iff 2y=8 \iff y=4

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