Final answer:
The function f(x) = 4(2)^(-x) - 3 approaches -3 as x approaches infinity and decreases without bound as x approaches negative infinity, with a horizontal asymptote at y = -3.
Step-by-step explanation:
The end behavior of a function describes what happens to the function's values as x approaches infinity or negative infinity. For the function f(x) = 4(2)^(-x) - 3, as x approaches infinity, the term 2^(-x) approaches zero, because any non-zero base raised to the power of negative infinity is zero. Thus, the function approaches -3. Conversely, as x approaches negative infinity, the term 2^(-x) grows exponentially, and the function's values decrease without bound, heading towards negative infinity. However, since f(x) involves a negative exponential function, the graph ultimately will approach the horizontal asymptote y = -3.