Question

Tx^2+3x-7=0 has two real solutions . what can b deduced about value of t ?​

Answer 1

The number of solutions of a quadratic equation

`ax^2+bx+c=0`

Depends on its discriminant

`\Delta = b^2-4ac`

• If
  `\Delta>0` there are two distinct solutions
• If
  `\Delta=0` there are two coincident solutions
• If
  `\Delta<0` there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

`b^2-4ac = 9+28t > 0 \iff t>-(9)/(28)`