Question

What are the possible lengths and widths of a rectangle if its length is 8 centimeters longer than the width, and the area is less than or equal to 33 square centimeters?

Answer 1

Length = 11

Width = 3

Explanation:

Conditions:

• It's length is 8 centimeters longer than the width
• The area is less than or equal to 33 square centimeters

L = W + 8

A ≤ 33

We know both the L and W have to be less than or equal to 33, as the maximum area would be 33 * 1.

First, find the factors of 33.

1, 3, 11, 33.

Put them in pairs.

1,33

3,11

Find the pair with the difference of 8.

33 - 1 = 32

11 - 3 = 8

Assign them to the Length or Width and test them against the conditions.

L = 11

W = 3

11 = 3 + 8

3 * 11 = 33