Use the function below to find F(1). F(t)=2•1/2^3t

Question

asked Apr 8, 2020 59.6k views

2 Answers

Andreas Frische · Answer 1 · 2020-04-09T16:52:03+0000

Answer:

Final answer is
$F\left(1\right)=0.2625$ .

Explanation:

Given function is
$F\left(t\right)=(2.1)/(2^3t)$ .

Now we need to use that function
$F\left(t\right)=(2.1)/(2^3t)$ to find the value of F(1).

F(1) means value of functino F(t) at t=1, So plug t=1 into given function.

$F\left(t\right)=(2.1)/(2^3t)$

$F\left(1\right)=(2.1)/(2^3(1))$

$F\left(1\right)=(2.1)/(8(1))$

$F\left(1\right)=(2.1)/(8)$

$F\left(1\right)=0.2625$

Hence final answer is
$F\left(1\right)=0.2625$ .

Robert Moore · Answer 2 · 2020-04-14T01:58:10+0000

Answer:

The solution is
F(1) = (1)/(4)

Explanation:

Given function is
2* (1)/(2^(3t))

We need to find the value of function
F(t) = 2* (1)/(2^(3t)) at t = 1

Replace t with 1 in
F(t) = 2* (1)/(2^(3t))

F(1) = 2* (1)/(2^(3(1)))

F(1) = 2* (1)/(2^(3))

F(1) = 2* (1)/(8)

F(1) = (2)/(8)

F(1) = (1)/(4)

Therefore, the solution is
F(1) = (1)/(4)