Question

When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because

7.5 mol of hydrogen would be needed to consume the available nitrogen.
7.5 mol of nitrogen would be needed to consume the available hydrogen.
hydrogen would produce 7.5 mol more ammonia than nitrogen.
nitrogen would produce 7.5 mol more ammonia than hydrogen.

Answer 1

Answer: A

Explanation: i just took the test and quick answer

Answer 2

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Step-by-step explanation:

• The balanced equation of the reaction of hydrogen with nitrogen is:

3H₂ + N₂ → 2NH₃

it is clear that 3mol of hydrogen react with 1 mol of Nitrogen to give 2 mol of ammonia.

• firstly, we need to calculate the number of moles of both

for H₂:

number of moles = mass / molar mass = (7.00 g) / (2.00 g/mol) = 3.5 mol.

for N₂:

number of moles = mass / molar mass = (70.00 g) / (28.00 g/mol) = 2.5 mol.

using cross multiplication

1 mol of N₂ needs → 3 mol of H₂

2.5 mol of N₂ needs → ??? mol of H₂

∴ the number of mol of H₂ needed = (3*2.5) / 1 = 7.5 mol

So, the right choice is:

7.5 mol of hydrogen would be needed to consume the available nitrogen.