Question

Can someone please help me

Answer 1

`\large\boxed{4\pi\ cm\approx12.56\ cm}`

Explanation:

The formula of a length of an arc:

`(\pi\alpha r)/(180^o)`

We have

`\alpha=120^o\\\\r=6\ cm`

Substitute:

`[tex]\hat{MN}=(\pi(120)(6))/(180)=4\pi\ cm\approx4(3.14)=12.56\ cm`