Question

What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +

Answer 1

It an expression or a way of saying f(x)=6x2+12-7

Answer 2

`x=-1+(√(78) )/(6)` and

`x=-1-(√(78) )/(6)`

Explanation:

`f(x) = 6x^2 + 12x - 7`

To find out the zeros of the quadratic function, we apply quadratic formula

`x=(-b+-√(b^2-4ac))/(2a)`

From the given f(x), the value of a=6, b=12, c=-7

Plug in all the values in the formula

`x=(-12+-√(12^2-4(6)(-7)))/(2(6))`

`x=(-12+-√(312))/(2(6))`

`x=(-12+-2√(78))/(2(6))`

Now divide each term by 12

`x=-1+-(√(78) )/(6)`

We will get two values for x

`x=-1+(√(78) )/(6)` and

`x=-1-(√(78) )/(6)`