Question

HELP!!

Polygon ABCDE has the vertices A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6). Polygon MNOPQ has the vertices M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).


A transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ is a


If polygon MNOPQ is translated 3 units right and 5 units down, it will coincide with a congruent polygon, VWXYZ, with its vertices at

Answer 1

1). Option C

2). Option A

Explanation:

The given vertices of polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8) and E(6, 6)

After reflection new polygon formed MNOPQ has the vertices M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8) and Q(-6, 6).

By comparing the vertices we find the x-coordinates of polygon ABCDE have been changed to MNOPQ by negative notation only.Y- coordinates are same.

Therefore, polygon ABCDE has been reflected across the y-axis.

Option C. is the answer.

If polygon MNOPQ is translated 3 units right and 5 units down then the new vertices of congruent polygon VWXYZ will be

M(-2, 8) = [(-2 - 3), (8 + 5)] = (-5, 13)

N(-4, 12) = [(-4 - 3), (12 + 5)] = (-7, 17)

O(-10, 12) = [(-10 - 3),(12 + 5)] = (-13, 17)

P(-8, 8) = [(-8 - 3), (8 + 5)] = (-11, 13)

Q(-6, 6) = [(-6 -3),(6 + 5)] = (-9, 11)

Therefore, Option A. is the correct option.