Answer:
21.5≤μ≤25.2
Explanation:
The formula for calculating confidence interval is expressed as;
CI = xbar±(z*s/√n)
xbar is the mean = 23.7
s is the standard deviation= 16.3
n is the sample size = 438
z is the z score at 95% confidence level
z = 1.96
Substitute into the formula
CI = 23.7±(1.96×16.3/√438)
CI = 23.7±(1.96×16.3/20.93)
CI = 23.7±(1.96×0.77788)
CI = 23.7±1.5264
CI = (23.7-1.5264, 23.7+1.5264)
CI = (21.4736, 25.2264)
The confidence interval to the nearest tenth is 21.5≤μ≤25.2