Question

Please help! Asap!

It’s only 1 question and I’m giving as many points possible!

Solve the system of equations algebraically. Show all of your steps.

y=x^2 + 2x

y=3x + 20

Answer 1

[-4,5]

STEP BY STEP EXPLANATION

ok, so first you plug in the equation 3x+20 into the y in the equation x^2+2x

Your new equation should be 3x+20=x^2+2x

Then you subtract 2x from both sides and your new equation should be x+20=x^2

Then you subtract 20 and x from both sides and your new equation should be 0=x^2-x-20

Then you multiply a with c, which is -20 and then you get b, which is -x or -1. After that you have to find two numbers that is the product of -20 and the sum of -1, which is -5 and 4

Then it would be (x-5)(x+4)=0. You you add 5 to both sides which will be x=5 and then you subtract 4 from both sides, which will be x=-4

Then your final answer is [-4,5]

hope this helped!