Question

When a fixed amount of ideal gas goes through an isochoric process:

its temperature must increase.
its pressure must increase.
its internal (thermal) energy does not change.
no heat enters or leaves the gas.
the gas does no work.

Answer 1

the gas does no work.

Step-by-step explanation:

An isochoric process is a process in which the volume of a gas is kept constant.

The work done by a gas during a transformation is given by:

`W=p\Delta V`

where

p is the gas pressure

`\Delta V` is the change in volume of the gas

For an isochoric process, the volume of the gas does not change, so

`\Delta V`

and so, according to the previous equation, the work done by the gas is zero:

W = 0