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Solve the equation for x 1/3 (6x-15) = 1/2(10x-4)

User JT Nolan
by
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1 Answer

6 votes

For this case we must solve the following equation for x:


\frac {1} {3} (6x-15) = \frac {1} {2} (10x-4)

We apply distributive property to the terms of parentheses:


2x-5 = 5x-2

We subtract 5x on both sides of the equation:


2x-5x-5 = -2\\-3x-5 = -2

Suamos 5 on both sides of the equation:


-3x = -2 + 5\\-3x = 3\\x = - \frac {3} {3}\\x = -1

Answer:


x = -1

User Ghiboz
by
5.6k points
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