Question

A bag contains 2 red marbles and 4 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is red?

Answer 1

Explanation:

Red = 2

Green = 4

P(G) = 4/6

P(R) = 2/5 (remember that 1 green marble is green. The total left is 5 so the 5 is not a typo)

P(G then R) = 4/6 * 2/5

P(G then R) = 2/3 * 2/5

P(G then R) = 4/15