Question

What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?

Answer 1

y-1=-4[x-(-3)]

Explanation:

Answer 2

`\large\boxed{y-1=-4(x+3)}`

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

We have m = -4 and the point (-3, 1). Substitute:

`y-1=-4(x-(-3))\\\\y-1=-4(x+3)`