Question

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

Answer 1

`{(x - 4)}^(2) + {y}^(2) = 12`

Step-by-step explanation

The equation of a circle given the center (h,k) and radius r is given by:

`{(x - h)}^(2) + {(y - k)}^(2) = {r}^(2)`

The circle has center (4,0) and radius

`r = 2 √(3)`

We substitute the center and radius to get,

`{(x - 4)}^(2) + {(y - 0)}^(2) = {(2 √(3)) }^(2)`

`{(x - 4)}^(2) + {(y - 0)}^(2) = 12`

`{(x - 4)}^(2) + {y}^(2) = 12`