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I need help finding the missing sides using the law of sines

I need help finding the missing sides using the law of sines-example-1

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4 votes

By the law of sines,


\frac{\sin\angle A}a=\frac{\sin\angle B}b=\frac{\sin\angle C}c

The interior angles of any triangle sum to 180 degrees in measure, so we know


m\angle A=(180-85-40)^\circ=55^\circ

Then


\frac{\sin55^\circ}a=(\sin85^\circ)/(26)\implies a\approx21

and


\frac{40^\circ}c=(\sin85^\circ)/(26)\implies c\approx17

User Jcalvert
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Check the picture below.

I need help finding the missing sides using the law of sines-example-1
User Trafalgarx
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