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In rhombus JKLM, if m<KLJ = 38°, find m<JIVIL. ​
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In rhombus JKLM, if m<KLJ = 38°, find m<JIVIL.
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In rhombus JKLM, if m<KLJ = 38°, find m<JIVIL. ​-example-1
User R Brennan
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1 Answer

2 votes

Answer:

∠JML = 104°

Explanation:

JL bisects angle KLM, so ...

∠KLM = 2·∠KLJ = 2·38° = 76°

Adjacent angles in any parallelogram are supplementary, so ...

∠JML = 180° -∠KLM = 180° -76°

∠JML = 104°

User Chris Rae
by
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