Question

If the zeros of the quadratic equation x^2+25=0 are +-5 (plus-minus 5), what is the correct factored form?

(x+5)(x-5)=0
(x+5i)(x-5i)=0
(x+12.5i)(x-12.5i)=0
(x+12.5)(x-12.5)=0

Answer 1

`(x + 5i)(x - 5i) = 0`

Step-by-step explanation

The given function is

`{x}^(2) + 25 = 0`

The zeros of this function are;

`x = \pm5i`

Or

`x = - 5i \: and \: x = 5i`

`x + 5i = 0\: and \: x - 5i = 0`

Hence the factored form is:

`(x + 5i)(x - 5i) = 0`

If the equation were:

`{x}^(2) - 25 = 0`

Then the factored form is

`(x + 5)(x - 5) = 0`