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Which inequality statement best represents the graph?

f(x) > –x2 + x – 1

f(x) < x2 + x – 1

f(x) < –x2 + x – 1

f(x) > x2 + x – 1

Which inequality statement best represents the graph? f(x) > –x2 + x – 1 f(x) &lt-example-1
User Balla
by
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2 Answers

1 vote

Answer:

f(x) < –x2 + x – 1

Explanation:

The graph is going down so we know that there is a maximum, therefore the A value has to be negative. This rules out f(x) < x2 + x – 1 and f(x) > x2 + x – 1 . The shaded area of the graph is below which indicates that f(x) has to be less than the function. This means the correct answer is f(x) < –x2 + x – 1 .

User Joel Bodenmann
by
8.7k points
5 votes

Answer:


y>-x^2 +x-1

Explanation:

Lets find the inequality that best describes the given statement

The graph of the parabola is upside down so the value of 'a' is -1

It means the equation for the parabola becomes
y=-x^2 +x-1

Now to get inequality , lets pick a point from the shaded part .

Lets pick (0,0), plug in 0 for x and 0 for y


y=-x^2 +x-1


0=-(0)^2 +(0)-1


0=-1

0 is greater than -1


y>-x^2 +x-1

User Vasanth Umapathy
by
8.2k points

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