211k views
3 votes
Simplify the complex fraction

((3x-7)/x^2)/(x^2/2)+(2/x)

I really need steps on how to do this properly cause I really can't figure it out
((3x-7)/(x^2) )/((x^2)/(2)+ (2)/(x) )

User Stuhlo
by
6.6k points

1 Answer

2 votes

Answer:

The simplest form is 2(3x - 7)/x(x³ + 4)

Explanation:

* Lets revise how can divide fraction by fraction

- To simplify (a/b)/(c/d), change it to (a/b) ÷ (c/d)

∵ a/b ÷ c/d

- To solve it change the division sign to multiplication sign and

reciprocal the fraction after the sign

∴ a/b × d/c = ad/bc

* Now lets solve the problem


((3x-7)/(x^(2)))/((x^(2))/(2)+(2)/(x))

- Lets take the denominator and simplify by make it a single

fraction, let the denominator of it 2x and change

the numerator


(x^(2))/(2)+(2)/(x)=(x(x^(2))+2(2))/((2)(x))=(x^(3)+4)/(2x)

∴ The fraction =
((3x-7)/(x^(2)))/((x^(3)+4)/(2x))

* Now lets change it by (up ÷ down)


(3x-7)/(x^(2)) ÷
(x^(3)+4)/(2x)

- Change the division sign to multiplication sign and reciprocal

the fraction after the sign


(3x-7)/(x^(2)) ×
(2x)/(x^(3)+4)


((2x)(3x-7))/((x^(2))(x^(3)+4))

- We can simplify x up with x down


(2(3x-7))/(x(x^(3)+4))

* The simplest form is 2(3x - 7)/x(x³ + 4)

User Ryszard Czech
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.